Factorise : $6 x^{2}+5 x-6$

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$6 x^{2}+5 x-6$

We have,           $a =6, b =5$ and $c =-6 $

$\therefore$  $l+ m=5$ and $lm = ac =6 \times(-6)=-36 $

$\therefore$   $l+ m =9+(-4) $

$\therefore$    $6 x ^{2}+5 x -6 =6 x ^{2}+9 x -4 x -6$

$=3 x (2 x +3)-2(2 x +3)=(2 x +3)(3 x -2)$

Thus,      $6 x ^{2}+5 x -6 =(2 x +3)(3 x -2) $

Similar Questions

Factorise : $3 x^{2}-x-4$

Verify whether the following are zeroes of the polynomial, indicated against them.

$p(x)=3 x^{2}-1,\,x=-\,\frac{1}{\sqrt{3}},\, \frac{2}{\sqrt{3}}$

Factorise : $x^{3}-3 x^{2}-9 x-5$

Check whether $-2$ and $2$ are zeroes of the polynomial $x + 2$.

Classify the following as linear, quadratic and cubic polynomials :

$(i)$ $x^{2}+x$

$(ii)$ $x-x^{3}$

$(iii)$ $y+y^{2}+4$